# A 25.0 mL sample of a solution of a monoprotic acid is titrated with a 0.115 M NaOH solution. The end point was obtained at about 24.8 mL. The concentration of the monoprotic acid is about ........ mol/L. A) 25.0 B) 0.0600 C) 0.240 D) 0.120 E) None of the above

The concentration of the acid is about 0.114 M (option E)

Explanation:

Step 1: Data given

Volume of the monoprotic acid = 25.0 mL = 0.025 L

Molarity of the monoprotic acid = ?

Molarity of the NaOH solution = 0.115 M

Volume NaOH = 24.8 mL = 0.0248 L

Step 2: Calculate the concentration

a*Cb * Vb = b * Ca * Va

⇒ a = the coeficient of NaOH = 1

⇒ Cb = the molarity of the acid = TO BE DETERMINED

⇒ Vb = the volume of the acid = 0.025 L

⇒ b = the coefficient of the acid = monoprotic = 1

⇒ Ca = the moalrity of NaOH = 0.115 M

⇒ Va = the volume of NaOH = 0.0248 L

1 * Cb * 0.025 = 1 * 0.115 * 0.0248

0.025 Cb = 0.002852

Cb = 0.11408 M

The concentration of the acid is about 0.114 M

## Related Questions

Given the electronegativities below, which covalent single bond is most polar? Element: H C N O
Electronegativity: 2.1 2.5 3.0 3.5
A) N-H B) O-C C) O-N D) C-H E) O-H

So the correct answer is e) O-H

Explanation:

To determine the most polar bond we calculate the electronegativity difference in each bond and determine the highest value:

a) N-H = 3.0 - 2.1 = 0.9

b) O-C = 3.5 - 2.5 = 1

c) O-N = 3.5 - 3 = 0.5

d) C-H = 2.5 - 2.1 = 0.4

e) O-H = 3.5 - 2.1 = 1.4

So the correct answer is e) O-H

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You have been working to develop a new fictitious compound in the lab. Determine the amount in units of moles​ [mol] of 20 grams​ [g] of this compound. The compound has the​ formula: upper x 2 upper y 2 upper z 7​, where the components are​ x, amu equals 47​; ​y, amuequals42​; ​z, amu equals 16.

From the chemical formula the total mass of the compound can be determined. The mass of the 1 mole of the compound is its molar mass. The atom by which the molecule is generated, the mass of these atoms are expressed in terms of amu or atomic unit mass, but after formation of a molecule in a particular ratio the mass of each of the atom becomes the total molecular weight of the generated molecule. In this case the molecule posses three atoms X, Y and Z which are in a ratio of 2:2:7. Thus the chemical formula of the compound can be written as .

So the total mass of the compound in amu is {(2×47)+(2×42)+(7×16)} = {94+84+112}=290 amu.

Thus 1 mole of the compound contains 290 amu or 290 g  by mass.

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In a zero order reaction, it takes 342 seconds for 75% of a hypothetical reaction to decompose. Determine the half-life t1/2} in units of seconds. Do not enter units with your numerical answer.

The half-life for a zero order reaction is .

Zero order reaction:

Zero-order reaction is a chemical reaction wherein the rate does not vary with the increase or decrease in the concentration of the reactant.

Let's calculate the rate constant for zero order reaction.

The expression used is:

where,

= initial concentration = 100

= final concentration = 25

t = time = 324 s

k = rate constant = ?

On substituting the values in the above formula:

In order to  calculate the half-life.

Therefore, the half-life is,

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Explanation :

First we have to calculate the rate constant for zero order reaction.

The expression used is:

where,

= let initial concentration = 100

= final concentration = 25

t = time = 324 s

k = rate constant = ?

Now put all the given values in the above expression, we get:

Now we have to calculate the half-life.

The expression used is:

Thus, the half-life is,