# The rate constant for this first‑order reaction is 0.460 s − 1 at 400 ∘ C. A ⟶ products How long, in seconds, would it take for the concentration of A to decrease from 0.680 M to 0.370 M?

1.32 seconds would take for the concentration of A to decrease from 0.680 M to 0.370 M.

Explanation:

Using integrated rate law for first order kinetics as:

Where,

is the concentration at time t

is the initial concentration

Given that:

The rate constant, k = s⁻¹

Initial concentration = 0.680 M

Final concentration = 0.370 M

Time = ?

Applying in the above equation, we get that:-

1.32 seconds would take for the concentration of A to decrease from 0.680 M to 0.370 M.

## Related Questions

A pogo stick bounces 30 M in 10 secs what is the bouncers average speed?

three  i hope this helps

I would love to help but it is 3 or is it 3 million?

Which statement best describes how dynamic equilibrium relates to a saturated solution of sodium chloride?

The dynamic equilibrium can be achieved from either side of the reaction i.e, from the direction of the reactants as well as from the direction of the products.

What is a saturated solution?

A solution in which no more solute can be dissolved at a given temperature is defined as the saturated solution. In such solution there will be highest capacity of solutes. For example NaCl in water at room temperature forms a saturated solution.

A dynamic equilibrium represents the state of a reversible reaction in which the rate of forward reaction equals to the rate of the backward reaction and the concentration of reactants and products remain the same.

The dynamic equilibrium of sodium chloride explains that each second, the amount of solid sodium chloride that dissolves equals the amount of solid chloride that recrystallizes.

At the point of equilibrium, no more measurable changes in the system can be noted.

To know more about dynamic equilibrium, visit;

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Each second, the amount of solid sodium chloride that dissolves equals the amount of solid sodium chloride that recrystallizes

A teacher wants to figure out the amount of a solution that is needed for a titration experiment in a class lab. The class has 15 students, and each experiment needs 50 mL of solution. If each student will perform the experiment two times, how many mL of solution will the teacher need for the whole class

1500 ml

Explanation:

You need to know how many milliliters will be used in this titration experiment, so if you have 15 students and each one uses 50 mL of solutions, you will multiply these numbers and obtain 750 ml, then you will perform the experiment twice, so you will need 750*2 = 1500 ml.

15 students times 50 mL per student. 750 mL Then 750 times two so you can do two experiments per person.

____________________ 2. what kind of solution contains more hydrogen ions than hydroxide ions?

HOPE THIS HELPED

Suppose the diver at the top of a 9 m high platform has a mass of 50.0 kg. Calculate her potential energy relative to the ground. Answer in Joules.

For the purpose we will use the following equation for potential energy:

U = m * g * h

In the above equation, m represents the mass of the object, h represents the height of the object and g represents the gravitational field strength (9.8 N/kg on Earth).

When we plug values into the equation, we get following:

U= 50kg * 9.8 N/kg *9m = 4410 J

How many ammonium ions and how many sulfate ions are present in a 0.270 mol sample of ?

Answer: There are ammonium ions and sulfate ions in the given amount of ammonium sulfate.

Explanation:

We are given 0.270 moles of ammonium sulfate and we need to find the number of ammonium and sulfate ions in it. The equation for the ionization of ammonium sulfate is given by the reaction:

By Stoichiometry,

1 mole of ammonium ions dissociates into 2 moles of ammonium ions and 1 mole of sulfate ion.

According to the mole concept:

1 mole of an ionic compound contains number of ions.

Hence, 0.270 mole of ammonium sulfate will contain number of ammonium ions and number of sulfate ions.

Hence, there are ammonium ions and sulfate ions in the given amount of ammonium sulfate.

A) Use bond enthalpies to estimate the enthalpy change for the reaction of hydrogen with ethene. H2(g) + C2H4(g) C2H6(g)

ANS:_____ kJ

(b) Calculate the standard enthalpy change for this reaction using heats of formation.

ANS:____kJ

(a) -134 kJ         (b) -136 kJ

Explanation:

a) Using the accounting of the  enthalpy  of broken and formed  bonds we will have the answer for this question ( remember the enthalpy of bonds broken are positive and those formed are negative)

ΔHrxn(kJ) = 6H (C-H) + 1 (C-C)+ 1H (H) + 1(C=C) + 4(C-H)

= 6(-411) +(-346) +432 + 602 + 4(411)

= - 134 kJ

(b) ΔHrxn = ΔHºf(C2H6) - ΔHºf (C2H4) = -83.75 kJ- 52.3 kJ =  -136 kJ

( ΔHºf (H2)) = 0)

If two electrons in the same atom have the same value of "l", they are If two electrons in the same atom have the same value of "l", they are in the same orbital. in the same level, but different sublevel. in the same sublevel, but not necessarily in the same level. in different levels and in different shaped orbitals. none of the above.

Explanation:

As we know that value of l depends on the value of n, that is, principle quantum number.

Since, relation between l and n is as follows.

l = (n - 1)

For example, suppose two electrons in the same atom have value of n = 2. So, the value of l will be as follows.

l = (2 - 1)

= 1

That means there will be s and p shells present in the atom. As the values of both l and n  are fixed. Therefore, electrons will be present in same level and same sub-shell.

Thus, we can conclude that none of the given statements are correct.

Which is more reactive, Rubidium or Hydrogen?