PHYSICS MIDDLE SCHOOL

A fair allocation of burdens and benefits in society is known as __________. A. induction B. distributive justice C. morality D. moral rules

Answers

Answer 1
Answer:

Answer : Distributive justice

Explanation : A fair allocation of burdens and benefits in society is know as distributive justice.

According to Armstrong distributive justice is the advantage and load of our lives are shared between members of a society.

Distribution justice is concerned with the fair allocation of advantage between different members of a society.

So, answers is the B.

Answer 2
Answer:

Answer:

Distributive justice

Explanation:

edg2020


Related Questions

HIGH SCHOOL

The greater the mass is in an object, the higher resistance to a change in movement the object will have. true or false

Answers

The correct answer is True

Explanation:

According to Newton's first law about motion, objects or bodies show a resistance to change their state this includes static objects or those that move. In this way, an object will not change its movement or state except if forces act on it, this is commonly known as inertia. Additionally, inertia and mass (quantity of matter) are closely related as the greater the mass the higher resistance, this can be explained as greater external forces are necessary to change the state of the object if the mass is greater. Thus, it is true the greater the mass is in an object, the higher the resistance to a change in movement the object will have.

True. Since Inertia states this law, we are bound to believe greater mass = greater resistance in change of motion
MIDDLE SCHOOL

The peak intensity of radiation from Star Beta is 350 nm. In what spectral band is this? UV, radio waves, visible light, or infared radiation

Answers

Answer:

UV (Ultraviolet Waves)

Explanation:

As we know that wavelength range of visible light is given as 450 nm to 750 nm.

so here as we move towards higher wavelength range then the energy of electromagnetic waves will decrease as we know it is given as

now on increasing wavelength we will shifted to infrared waves while on decreasing the wavelength energy of electromagnetic waves will increase and this will shift towards ultraviolet waves

Since the given wavelength is less than the wavelength of visible light so here it is Ultraviolet Waves

I say uv all the way
HIGH SCHOOL

Which of the following statements are true concerning stable nuclei? Check all that apply.

There is no limit to the size of a stable nucleus because of the great strength of the strong nuclear force.
Heavy stable nuclei tend to contain more protons than neutrons.
There is a limit to the size of a stable nucleus because of the short range of the strong nuclear force.
Heavy stable nuclei tend to contain roughly the same number of protons as neutrons.
Heavy stable nuclei tend to contain fewer protons than neutrons.

Answers

Answer:

There is a limit to the size of a stable nucleus because of the short range of the strong nuclear force.

Heavy stable nuclei tend to contain roughly the same number of protons as neutrons.

Explanation:

An atomic nuclei consist of nucleons which are protons and neutrons that occupies the central part of atoms.

A stable nuclei is one in which the number protons and neutron have roughly the same number. In an unstable nuclei, the proton or the neutron number balance is tipped. This imbalance is what results in radioactively and causes some of these nuclear particles to be radiated. The decay of an unstable nuclei would eventually result into an atom achieving stability as either the excess proton or neutron is lost.

In terms of nuclear force, the force keeps the repulsion between similarly charged protons in an atom in balance. If an atom is stable, the nuclear force would keep the size of the nucleus from expanding excessively outwards.

In an unstable nucleus, the repulsion would be great and the nucleus would begin to expand outwards. This would result in growing size of the atom.

MIDDLE SCHOOL

5. Which set of listed parameters would result in the greatest number of Gs at the bottom of a loop (location C)?
a. Height at A = 50.0 m, Height at B = 30.0 m, Radius at C = 20.0 m
b. Height at A = 60.0 m, Height at B = 45.0 m, Radius at C = 20.0 m
c. Height at A = 60.0 m, Height at B = 35.0 m, Radius at C = 25.0 m
d. Height at A = 80.0 m, Height at B = 60.0 m, Radius at C = 50.0 m

Answers

C is correct friends
Answer Is C Guys !!!!!
HIGH SCHOOL

The triple point of water is 273.1598 K or 0°C at 611.73 pascals of pressure. If ice is heated at pressures below the triple point, what will be the result A) the ice melts but the water never boils

B) ice changes to a liquid and then to a gas

C) the ice passes directly into the gaseous state

D) the ice remains solid at pressures lower than the triple point

Answers

Answer:

c) the ice passes directly into the gaseous state.

Explanation:

Since the pressure decreases, the molecules of water can jump directly from solid to gas because there is any atmospheric pressure that maintain them sticky.

At pressures below the triple point, a solid "sublimes" ... When it's heated, it turns directly into gas, without ever being a liquid. We never see water do that, because the triple point pressure of water is so low ... less than 1% of the normal atmospheric pressure that we're used to. It's actually pretty close to the atmospheric pressure on Mars. So on Mars, ice cubes would behave like 'dry ice' acts here ... You'd see a cloud swirling around it and then disappear, as the ice turned to water vapor. But there would never be a puddle.
HIGH SCHOOL

Colonel John P. Stapp, USAF, participated in studying whether a jet pilot could survive emergency ejection. On March 19, 1954, he rode a rocket-propelled sled that moved down a track at a speed of 632 mi/h. He and the sled were safely brought to rest in 1.40 s. Col. John Stapp and his rocket sled are brought to rest in a very short time interval. Stapp's face is contorted by the stress of rapid negative acceleration. (Courtesy of U.S. Air Force) (a) Determine the negative acceleration he experienced (in m/s2). m/s2 (b) Determine the distance he traveled during this negative acceleration (in m). m (c) What If? Col. Stapp was able to walk away from this experiment. If the human body can survive a negative acceleration five times that experienced by Col. Stapp, what minimum stopping time (in s) would this correspond to in the 1954 experiment?

Answers

(a)

First of all, let's convert the initial velocity from miles/hour to m/s:

Then we can find the acceleration by using the equation:

where:

v = 0 is the final velocity

u = 282.5 m/s is the initial velocity

t = 1.40 s is the time interval

Substituting into the equation,

(b) 197.7 m

We can find the stopping distance by using the SUVAT equation:

where

v = 0 is the final velocity

u = 282.5 m/s is the initial velocity

is the acceleration

d is the distance travelled while stopping

Solving for d, we find

(c) 0.28 s

In this case, the acceleration is five time that experienced in the previous experiment:

We can find the stopping time by using the equation:

where

v = 0 is the final velocity

u = 282.5 m/s is the initial velocity

Since we have the acceleration, we can re-arrange the formula to find the time:

COLLEGE

A bar magnet is dropped toward a conducting ring lying on the floor. As the magnet falls toward the ring, does it move as a freely falling object

Answers

Consider that the bar magnet has a magnetic field that is acting around it, which will imply that there is a change in the magnetic flux through the loop whenever it moves towards the conducting loop. This could be described as an induction of the electromotive Force in the circuit from Faraday's law.

In turn by Lenz's law, said electromotive force opposes the change in the magnetic flux of the circuit. Therefore, there is a force that opposes the movement of the bar magnet through the conductor loop. Therefore, the bar magnet does not suffer free fall motion.

The bar magnet does not move as a freely falling object.

COLLEGE

Ultraviolet light with wavelength λ = 300 nm falls on a cesium surface. The kinetic energy of emitted photoelectrons is 2.1 eV. What is the work function of cesium? What is the maximum wavelength of light for the photoelectric effect to occur for cesium?

Answers

Answer:

The equation of photoelectric effect is given as,

hf = Kmax + work function

Kmax is the kinectic energy of the emitted electron, hf is photon energy transferred to a single electron in the material of the target.

From the equation above,

Work function = hf - Kmax.

hf = hc/wavelength

h = 6.63 x 10^-34J.S, c = 2.98 x 10^8m/s, wavelength = 300nm = 300 x 10^-9m, Kmax = 2.2eV = 2.2 x 1.6 x10^-19.

Work function = [( 6.63 x 10^-34 J.S * 2.28 x 10^8 m/s)/(300 x 10^-9)] - [2.2 * 1.6 x 10^-19]

work function = 3.07 x 10^-19V = 1.92eV

Maximum wavelength of light for photoelectric effect to occur in cesium

Wavelength = c/f. with f known, that wavelength can be calculated from the equation

MIDDLE SCHOOL

The FIRST step in cloud formation is.... A) warmed air cools and condenses. B) solar energy causes warm air to rise. C) solar energy causes water vapor to condense.

Answers

c because the fist step is condensing then rising up

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