To determine the density of an empty plastic jug, you would measure A) it on a scale.
B) it with a ruler.
C) the mass and volume.
D) the length and volume.


Answer 1
Answer: I think the answer is (C) mass and volume
Answer 2


C) the mass and volume


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The moon Phobos orbits Mars (mass = 6.42 x 1023 kg) at a distance
of 9.38 x 106 m. What is its period of


is the period of orbit.


The equation that is useful in describing satellites motion is Newton form after Kepler's Third Law. The period of the satellite (T) and the average distance to the central body (R) are related as the following equation:



T is the period of the orbit

R is the average radius of orbit

G is gravitational constant  

Here, given data

Substitute the given values, we get T as




Taking square root, we get



27583.78 s




Two rockets are fired at each other with initial velocities of 150m/s150m/s and are 6000m6000m apart. The first rocket is accelerating at 5m/s25m/s2 while the second is accelerating at 15m/s215m/s2 . How far has the second rocket gone (in meters) when they collide? A :



3469.788 m


t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

First rocket

Second rocket

When this will collide the total distance they would have covered would be 6000 m.

Hence at 13.72 seconds they will collide assuming they are launched at the same time.

The second rocket would have gone 3469.788 m when they collide


Which property is characterized by the ability to bend?


Definition: Malleability is the quality of something that can be shaped into something else without breaking, like the malleability of clay. Malleability — also called plasticity — has to do with whether something can be molded.

the answer is malleable


michelle withdrew 120$ from her bank account. she now has 3345$ in her account qrite and solve an equation to find how much money m was in her account before she made the withdrawal


He had $3,465 before he with drew $120
3345+120=$3465 she had $3465 before the withdrawal

A 900-kg car traveling east at 15.0 m/s collides with a 750-kg car traveling north at 20.0 m/s. The cars stick together. What is the speed of the wreckage just after the collision?



12.2 m/s


Initial momentum = final momentum

In the x direction:

(900 kg) (15.0 m/s) = (900 kg + 750 kg) vx

vx = 8.18 m/s

In the y direction:

(750 kg) (20.0 m/s) = (900 kg + 750 kg) vy

vy = 9.09

The magnitude of the velocity is therefore:

v = √(vx² + vy²)

v = 12.2 m/s


What kind of light results when the total spectrum of refracted light is recombined? violet green white red?


The final light will be white. In fact, each color of the visible spectrum is an electromagnetic wave with its own specific frequency and wavelength. White, instead, does not have a specific frequency: it is the sum of all the different wavelengths of the visible spectrum. Therefore, when recombining the spectrum of the refracted light all the different frequencies recombine together, and their sum gives white light.


Which statement is true? A) All waves travel at the same speed through any medium. B) All waves travel at the same speed if no medium is present. C) Electromagnetic waves require a medium, but mechanical waves do not. D) Mechanical waves require a medium, but electromagnetic waves do not. Eliminate


D) Mechanical waves always require a medium, while electromagnetic waves do not and can thus travel through open space.
I just took the test and it D . have a good day

If a 25.5 kg child climbs 2 steps of 20 cm each, the work performed is


M = 25.5 kg, the mass of the child
h = 2*20 = 40 cm = 0.4 m
g = 9.8 m/s², acceleration due to gravity.

The work done is equal to the increase in PE (potential energy).
Therefore the work done is
W = (mg)*h
    = (25.5*9.8 N)*(0.4 m)
    = 99.96 J

Answer: 99.96 J


To practice Tactics Box 9.1 Calculating the Work Done by a Constant Force. Recall that the work W done by a constant force F⃗ at an angle θ to the displacement Δr⃗ is W=F⃗ ⋅ Δr⃗ =FΔrcosθ. The vector magnitudes F and Δr are always positive, so the sign of W is determined entirely by the angle θ between the force and the displacement.



See espplanation below.


The deduction of the formula given is this one:

We can assume that we have a constant force F acting on a point that follows a curve Y with a velocity v at each instant, we can define an small amount of work who occurs on a instant dt and we can calculate it as:

And we have that Fv represent the power at the instant dt and we can sum all the small amounts for the work in the entire trajectory with the following integral:

And M represent the trajectory from to

If we assume that the force is constant so then we can do this with the integral:

Where represent the displacement of the point along the curve.

We know that the fot product can be expressed on this way:

Where represent the angle between the force vector and the direction of the movement, so in general we have this:

And as we can see F and are scalars (assumed constant both) and not affect the sign of the work, so the only value that affect the sign of W is the angle since depedens of the cosine function who is maximum at 0 and 2\pi and minimum at


The vector magnitudes F and r are always postive, so the sign o W is determined entirely by the angle e between the force and the displacement.Submit Figure 1 off 1 part C

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