If a person weighs 717 N on earth and 5320 N on the surface due to gravity on that planet? of a nearby planet, what is the acceleration a. 83.6

b. 72.7

c. 63.2

d. 53.1


Answer 1



It is given that,

Weight of the person on Earth, W = 717 N

Weight of a person is given by the following formula as :

g is the acceleration due to gravity on earth

m = 73.08 kg

The mass of an object is the amount of matter contained in it. It is same everywhere.

Let W' is the weight of the person on the surface of a nearby planet, W' = 5320 N

g' is the acceleration due to gravity on that planet. So,



So, the acceleration due to gravity on that planet is . So, the correct option is (b). Hence, this is the required solution.     

Answer 2

The answer is B. You divide 717 by the acceleration by gravity of earth (9.8 m/s) and divide 5320 by your answer.

Related Questions


A roller-coaster car has a mass of 1080 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 16 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction) FN on the car from the track if the car's speed is v = 7.6 m/s? (b) What is FN if v = 17 m/s? Use g=9.81 m/s^2.



(a): The normal force on the car  from the track when the car's speed is v= 7.6 m/s  is  FN= -6696 N.

(b): The normal force on the car from the track when the car's speed is v= 17 m/s is FN= 8912.7 N.


m= 1080 kg

r= 16m

v1= 7.6 m/s

v2= 17 m/s

g= 9.81 m/s²

v1= w1*r

w1= v1/r

w1= 0.475 rad/s

ac1= w1² * r

ac1= 3.61 m/s²

FN= m * (ac1 - g)

FN= -6696 N    (a)


v2= w2*r

w2= v2/r

w2= 1.06 rad/s

ac2= w2² * r

ac2= 18.06 m/s²

FN= m * (ac2 - g)

FN= 8912.7 N    (b)


Noise reduction headphones actively produce their own sound waves in order to cancel out external sound waves. A microphone in the headphones receives waves of one frequency. A loudspeaker in the headphones then produces a wave of that frequency but of a different phase. What is the phase difference between the external sound wave and the wave produced by the loudspeaker in the headphones? A. 90 B.180 C 270 D 360


If you want to use it to cancel out the external wave, then it has to be exactly the same frequency and exactly 180 degrees out of phase.

The velocity of sound in sea water is 1533 m/s. find the bulk modulus (in n/m2) of sea water if its density is 1.025 ´ 103 kg/m3.


The speed of sound in a medium is given by:

Ks is the bulk modulus
is the medium density

In our problem,  and , so if we re-arrange the previous equation we can find the bulk modulus of sea water:


Bulk modulus,


Given that,

The velocity of sound in sea water, v = 1533 m/s

Density of water,

We need to find the bulk modulus. The speed of sound also depends on the bulk modulus of the material. The relationship is given by :

So, the bulk modulus of the sea water is . Hence, this is the required solution.


Which Best exsplains the Statement “It has no definite volume”





Gaseous state of substance has no definite volume.


paperclips are more dense than water. however, it's possible to make them float. what property of water allows this? how does this property relate to the molecular structure of water


Is it surface tension?

To find the acceleration you must calculate the change in distance during each unit of time is this true or false?


This is false.  To find the magnitude of acceleration during some
time interval, all you need to know is the speed at the beginning
and end, and the length of the time interval.

Then          |Acceleration| = (change in speed) / (time for the change) .


When is a body said to be at rest


rest is the state of a body which is stationary relative to a particular frame of reference or another object.  When the state of a body does not changes with time with respect to its surroundings in a particular frame of reference that time  it is said to be at rest.

in other words we can say that when a body has zero velocity and its position is not changing with time relative to its surrounding then it is said to be at rest.

For example a chair on which you are sitting is at rest or a table on which your desktop is kept is rest because its position is not changing.


when it dies , and has left for heaven.


a few minuites after the body has died and was buried , the body is at rest when the person is with god.


Which of the following information is necessary to describe an object’s motion?


Distance and time...............
Distance and tim......

the base of a rectangular vessel measure 10m by 18cm. water is poured into a depth of 4cm. (a) what is the pressure on the base?. (b) what is the thrust on the base?.​


a). The pressure that lies on the base would be:

b). The thrust that exists on the base would be:

a). Given that,

Length of the rectangular vessel

The Breadth of the rectangular vessel

Area of the vessel ×


To find the pressure,

Pressure(p) = Density × g × h



Gravity(g) =

Height(h) = or


P × ×

b). Since,


⇒ ×

⇒ ×

∵ Thrust or Force

Learn more about "Pressure" here:


a) P =392.4[Pa]; b) F = 706.32[N]


With the input data of the problem we can calculate the area of the tank base

L = length = 10[m]

W = width = 18[cm] = 0.18[m]

A = W * L = 0.18*10

A = 1.8[m^2]


Pressure can be calculated by knowing the density of the water and the height of the water column within the tank which is equal to h:

P = density * g *h


density = 1000[kg/m^3]

g = gravity = 9.81[m/s^2]

h = heigth = 4[cm] = 0.04[m]

P = 1000*9.81*0.04

P = 392.4[Pa]

The force can be easily calculated knowing the relationship between pressure and force:

P = F/A

F = P*A

F = 392.4*1.8

F = 706.32[N]

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